In the charging of a capacitor,what is the co | vedclass

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(B) Ampere's circuital law states that $\oint B \cdot dl = \mu_0 I_{enclosed}$.Consider a parallel plate capacitor being charged. If we choose a flat

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The law gives different values for the magnetic field at the same point depending on the surface chosen.

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(B) Ampere's circuital law states that $\oint B \cdot dl = \mu_0 I_{enclosed}$.Consider a parallel plate capacitor being charged. If we choose a flat circular surface between the plates,the current passing through it is zero,implying $B = 0$.However,if we choose a balloon-shaped surface with the same boundary,the conduction current $I_c$ passes through it,implying $B 
eq 0$.This contradiction arises because Ampere's law does not account for the time-varying electric field between the plates,which acts as a displacement current $I_d = \epsilon_0 \frac{d\phi_E}{dt}$.Thus,the law is incomplete for non-steady currents.

$A$. $\oint E \cdot dA$	$(i)$ $0$
$B$. $\oint B \cdot dA$	$(ii)$ $-\frac{d\phi_B}{dt}$
$C$. $\oint E \cdot dl$	$(iii)$ $\frac{Q}{\varepsilon_0}$
$D$. $\oint B \cdot dl$	$(iv)$ $\mu_0(i_c + i_d)$

In the charging of a capacitor,what is the contradiction in Ampere's circuital law?

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